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5x^2-43x=24
We move all terms to the left:
5x^2-43x-(24)=0
a = 5; b = -43; c = -24;
Δ = b2-4ac
Δ = -432-4·5·(-24)
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{2329}}{2*5}=\frac{43-\sqrt{2329}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{2329}}{2*5}=\frac{43+\sqrt{2329}}{10} $
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